Hapi Stop

Hapi Stop

Pikja droing i kam long Ben Rowberry

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Buk blong Momon Tresa Han

Statem wetem kwestin A. Afta yusum ansa blong kwestin antap blong fulumap fas emti laen we i stap long nekis kwestin. Long en yu bae gat ol skripja refrens blong 2024 yut stamba toktok.

1. Stat long 1 Nifae 1:9–10. ?Hamas “narafala man” nao Nifae i bin luk we oli stap folem “Wan” (Sevya)? __________

2. Go long Omnae 1:[A]________. ?Huia nao hem i kam king blong graon blong Sarahemla? _______

3. Go long [B]________ 17:2. ?Hu nao i biliv long ol toktok blong Abinadae? ___________

4. Go long [C]________ 53:22. ?Huia nao i maj long fored blong olgeta 2,000 yang soldia ? ______

5. Go long [D]_________ 14:2. ?Bae i tekem hamas yia blong Sevya i kam? __________

6. Go long Mosaea 6:[E]_______. ?Hamas moa yia nao King Benjamin i bin laef? ___________

7. Go long 2 Nifae [F]______:25. ?Ol toktok blong hu nao Lihae i talem long Josef blong lisin gud long hem? ___________

8. Go long 2 [G]_______ 23. Japta heding i talem blong komperem Aesea long ________.

2024 Skripja Stamba Toktok : [F]_____ [G]________ [E]_____:[H]______

?Wanem nao skripja ia i minim long yu?

Ol ansa oli stap long pej 31.

Tri blong laef Mes gem

I gat wan rod nomo we i lid i go long tri blong laef. ?Yu yu save faenemaot wijwan long olgeta?

Ansa blong luk i stap long ftsoy.ChurchofJesusChrist.org.

Translesen Taem

?Long wanem yia nao Josef Smit i bin finisim translesen blong ol buk we oli wokem long gol? Blong faenemaot hemia, bae yu mas mekem wan gem taem yu “transletem” ol sep i go long ol namba we oli ripresentem. Afta mekem matematik problem long en.

Not: Wanwan sep i ripresentem wan spesifik namba. Long olgeta we oli stap lukaotem wan jalenj, problem kwestin gem ia i save ansarem we yu no nidim eni help. Be sapos yu fas, sam long ol pat blong ansa oli putum i stap, long en blong pej be oli raetem i lukluk i gobak antap.

1. [traengol] + [traengol] + [traengol] = [rektangol]

2. [rektangol] – [trapesod] = [heksagon]

3. [heksagon] ÷ [Dimond] = [trapesod]

4. [Dimond] x ½[Dimond] = 8

5. [traengol] x [trapesod] = [rektangol]

Matematik Problem:

([rektangol] x [traengol]) + (1/2[Dimond]) = [defren kaen sep]

([defren kaen sep] x [rektangol] x [traengol]) + [Dimond] – 100 = _______________.

Ansa long pej 31. Ansa blong luk i stap long ftsoy.ChurchofJesusChrist.org.

Pat blong ansa 1: Lukluk kolosap long laen A mo E long wan saed mo nara wan long narasaed.

Pat blong ansa namba 2: Yu stak yet? Long A, tri [traengol] = [rektangol]. Insaed long E, wan [traengol] x wanem = [rektangol]?

Pat blong ansa namba 3: I stret, I stret. [Trapesod] = 3.

Ol Komik

komik

Nogud pat blong stap olsem smol brata blong Golaeat hem i blong werem ol klos blong hem.

Val Chadwick Bagley

Ol Ansa

Ol Ansa blong Hapi Stop: Buk blong Momon Tresa Hunt: A. 12; B. Mosaea; C. Alma; D. Hileman; E. 5; F. 3; G. Nifae; H. 13 Translesen Taem: 1829

Buk blong Momon Tresa Hunt

1. 12

2. Mosaea

3. Alma

4. Hileman

5. 5

6. 3

7. Nifae

8. 13

Stamba Skripja: 3 Nifae 5:13

Translesen Taem

1829