1979
Whose Shoes?
November 1979


“Whose Shoes?” Friend, Nov. 1979, inside back cover

Whose Shoes?

Can you solve this puzzle? A set of shoes equals the number of shoes each creature needs to fit all its feet. Number (1) is filled in to start you off.

  1. Spider bought enough shoes for her 36 children.

  2. If Bee needs fewer shoes than Spider, write 226; if not, write 337.

  3. Pig had 111 sets of shoes. How many single shoes did she have to shine?

  4. Spider met Centipede who said, “My name means ____ feet.”

  5. Bee bought 13 sets of shoes; Bird bought 3 pairs; together they had ____ shoes.

  6. From 216 single shoes that Spider gave him, Bee made ____ sets of shoes.

  7. Pig had to clean ____ shoes because 34 sets became muddy.

  8. Bird wove 25 pairs of slippers from grass and tied ____ bows to decorate them.

  9. Pig paid $6.00 a set for 9 sets of shoes for a total of ____.

  10. Bird liked to brag, “I have 12 pairs of shoes and 1 extra one for every day in May.” How many shoes does Bird have?

  11. If Bird, Spider, Bee, and Pig gave 20 mice enough old shoes to make 210 sets with one extra, how many shoes would the mice have?

  12. Bee put 58 sets of shoes in boxes each 5 millimeters high. Stacked on top of each other they measured ____ millimeters high.

  13. Bird kicked 9 different rocks each day along the path for 30 days. Those ____ rocks wore his new shoes out.

Answers:

  • (1) 288, (2) 226, (3) 444, (4) 100, (5) 84, (6) 36, (7) 136, (8) 50, (9) 54, (10) 775, (11) 841, (12) 290, (13) 270.

Illustrated by Colleen Hinckley